最小生成树C代码实例
在贪婪算法这一章提到了最小生成树的一些算法,首先是Kruskal算法,实现如下:
MST.h
#ifndef H_MST#define H_MST#define NODE node *#define G graph *#define MST edge **/* the undirect graph start */typedef struct _node { char data; int flag; struct _node *parent;} node;typedef struct _edge { node *A; node *B; int w;} edge;typedef struct _graph { node **nodelist; int nodeLen; edge **edgelist; int edgeLen;} graph;/* the undirect graph end */int kruskal(G , edge *[]);int makeset(NODE);int find(NODE , NODE);int merge(NODE , NODE);int comp(const void *, const void *);#endif
MST.c
#include "mst.h"#include#include int main(int argc, char *argv[]){ /* Construct the undirect connected graph */ graph g; g.nodeLen = 6; g.edgeLen = 10; node node_a, node_b, node_c, node_d, node_e, node_f; edge edge_1, edge_2, edge_3, edge_4, edge_5, edge_6, edge_7, edge_8, edge_9, edge_10; node_a.data = 'a'; node_a.flag = 0; node_a.parent = (node *)malloc(sizeof(node)); node_b.data = 'b'; node_b.flag = 0; node_b.parent = (node *)malloc(sizeof(node)); node_c.data = 'c'; node_c.flag = 0; node_c.parent = (node *)malloc(sizeof(node)); node_d.data = 'd'; node_d.flag = 0; node_d.parent = (node *)malloc(sizeof(node)); node_e.data = 'e'; node_e.flag = 0; node_e.parent = (node *)malloc(sizeof(node)); node_f.data = 'f'; node_f.flag = 0; node_f.parent = (node *)malloc(sizeof(node)); edge_1.A = &node_a; edge_1.B = &node_b; edge_1.w = 5; edge_2.A = &node_a; edge_2.B = &node_c; edge_2.w = 6; edge_3.A = &node_a; edge_3.B = &node_d; edge_3.w = 4; edge_4.A = &node_b; edge_4.B = &node_c; edge_4.w = 1; edge_5.A = &node_b; edge_5.B = &node_d; edge_5.w = 2; edge_6.A = &node_c; edge_6.B = &node_d; edge_6.w = 2; edge_7.A = &node_c; edge_7.B = &node_e; edge_7.w = 5; edge_8.A = &node_c; edge_8.B = &node_f; edge_8.w = 3; edge_9.A = &node_d; edge_9.B = &node_f; edge_9.w = 4; edge_10.A = &node_e; edge_10.B = &node_f; edge_10.w = 4; node **nodelist; nodelist = (node **)malloc(sizeof(node *) * g.nodeLen); edge **edgelist; edgelist = (edge **)malloc(sizeof(edge *) * g.edgeLen); nodelist[0] = &node_a; nodelist[1] = &node_b; nodelist[2] = &node_c; nodelist[3] = &node_d; nodelist[4] = &node_e; nodelist[5] = &node_f; edgelist[0] = &edge_1; edgelist[1] = &edge_2; edgelist[2] = &edge_3; edgelist[3] = &edge_4; edgelist[4] = &edge_5; edgelist[5] = &edge_6; edgelist[6] = &edge_7; edgelist[7] = &edge_8; edgelist[8] = &edge_9; edgelist[9] = &edge_10; g.nodelist = nodelist; g.edgelist = edgelist; edge *X[g.nodeLen-1]; int e = 0; while (e < g.edgeLen) { printf("%c-%c %d/n", g.edgelist[e]->A->data, g.edgelist[e]->B->data, g.edgelist[e]->w); e++; } printf("------------------------------------------------------/n"); kruskal(&g, X); e = 0; while (e < (g.nodeLen-1)) { printf("%c-%c %d/n", X[e]->A->data, X[e]->B->data, X[e]->w); e++; }}int kruskal(G g, edge *pX[]){ int i, j; /* Initially every disjoint set have one node */ for (i = 0; i < g->nodeLen; i++) makeset(g->nodelist[i]); /* sort the edgelist */ qsort(g->edgelist, g->edgeLen, sizeof(edge *), comp); int e = 0; while (e < g->edgeLen) { printf("%c-%c %d/n", g->edgelist[e]->A->data, g->edgelist[e]->B->data, g->edgelist[e]->w); e++; } printf("------------------------------------------------------/n"); node da, db; da.parent = (node *)malloc(sizeof(node)); db.parent = (node *)malloc(sizeof(node)); for (j = 0; j < g->edgeLen; j++) { find(g->edgelist[j]->A, &da); find(g->edgelist[j]->B, &db); if (da.data != db.data) { merge(g->edgelist[j]->A, g->edgelist[j]->B); *pX++ = g->edgelist[j]; } }}int makeset(NODE n){ n->parent = n;}int find(NODE n, NODE ds){ if (n->parent == n) { ds->data = n->data; ds->flag = 1; ds->parent = n->parent; } if (n->parent != n) find(n->parent, ds);}int merge(NODE da, NODE db){ if (da->flag) db->parent = da; else da->parent = db;}int comp(const void *ea, const void *eb){ if ((*(edge **)ea)->w > (*(edge **)eb)->w) return 1; else if ((*(edge **)ea)->w == (*(edge **)eb)->w ) return 0; else return -1;}
在实现这个算法的时候,真正体会到了测试的重要性。程序能成功编译只是完成了一小部分,必须经过反复的测试才能发布。
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